Wipro Talent Next Milestone 4 Coding Questions 2024 (With Solutions)

Wipro Talent Next Milestone 4 Coding Questions 2024 | Wipro Talent Next Milestone Coding Questions | Wipro Talent Next Milestone 4 Coding Questions & Answers | Wipro Talent Next Milestone 4 Sample Coding Questions

Wipro Talent Next Milestone 4 Coding Questions 2024:  Aspirants who pass in the Online Test will qualify for the coding test process. The coding test will be conducted for the process to check the candidate’s capability. The Wipro Talent Next Milestone 4 Coding Questions will be asked in any language. In the below section, we have provided the Java, C, C++, and Python Coding Questions with Solutions. With the clear Explanation, we have provided all the details here.

Wipro Milestone 3 Coding Questions & Answers

Wipro Milestone 1 Coding Questions

Solve the Frequently Asked coding test Questions to help with your study. Before entering the coding test, aspirants can start their preparation by downloading or viewing the practice questions. Here we have provided the study material for the coding test. More details like Wipro Talent Next Milestone 4 Coding Questions, Wipro Talent Next Milestone 4 Coding Questions With Answers, Salary, Hike, Increment, Annual Appraisal, etc. on this page.

Wipro Talent Next Milestone 4 Coding Questions With Solutions

QUESTIONS) Check whether two Strings are anagram of each other

Input

“gram”
“arm”

Solution:

PYTHON PROGRAM

// C++ program to check whether two strings are anagrams
// of each other
#include <bits/stdc++.h>
using namespace std;

/* function to check whether two strings are anagram of
each other */
bool areAnagram(string str1, string str2)
{
    // Get lengths of both strings
    int n1 = str1.length();
    int n2 = str2.length();

    // If length of both strings is not same, then they
    // cannot be anagram
    if (n1 != n2)
        return false;

    // Sort both the strings
    sort(str1.begin(), str1.end());
    sort(str2.begin(), str2.end());

    // Compare sorted strings
    for (int i = 0; i < n1; i++)
        if (str1[i] != str2[i])
            return false;

    return true;
}

// Driver code
int main()
{
    string str1 = "gram";
    string str2 = "arm";

    // Function Call
    if (areAnagram(str1, str2))
        cout << "The two strings are anagram of each other";
    else
        cout << "The two strings are not anagram of each "
                "other";

    return 0;
}
C++ PROGRAM

# your code goes here

class Solution:

    # Function is to check whether two strings are anagram of each other or not.
    def isAnagram(self, a, b):

        if sorted(a) == sorted(b):
            return True
        else:
            return False

# {
# Driver Code Starts

if __name__ == '__main__':
    a = "gram"
    b = "arm"
    if(Solution().isAnagram(a, b)):
        print("The two strings are anagram of each other")
    else:
        print("The two strings are not anagram of each other")
Output

The two strings are not anagram of each other

QUESTIONS)  Pythagorean Triplet in an array

Input

{10, 4, 6, 12, 5}

Solution:

PYTHON PROGRAM

#include <iostream>

using namespace std;

// Returns true if there is Pythagorean triplet in ar[0..n-1]
bool isTriplet(int ar[], int n)
{
    for (int i = 0; i < n; i++) {
        for (int j = i + 1; j < n; j++) {
            for (int k = j + 1; k < n; k++) {
                // Calculate square of array elements
                int x = ar[i] * ar[i], y = ar[j] * ar[j], z = ar[k] * ar[k];

                if (x == y + z || y == x + z || z == x + y)
                    return true;
            }
        }
    }

    // If we reach here, no triplet found
    return false;
}


int main()
{
    int ar[] = { 10, 4, 6,12, 5 };
    int ar_size = sizeof(ar) / sizeof(ar[0]);
    isTriplet(ar, ar_size) ? cout << "Yes" : cout << "No";
    return 0;
}
C++ PROGRAM

#include <iostream>

using namespace std;

// Returns true if there is Pythagorean triplet in ar[0..n-1]
bool isTriplet(int ar[], int n)
{
    for (int i = 0; i < n; i++) {
        for (int j = i + 1; j < n; j++) {
            for (int k = j + 1; k < n; k++) {
                // Calculate square of array elements
                int x = ar[i] * ar[i], y = ar[j] * ar[j], z = ar[k] * ar[k];

                if (x == y + z || y == x + z || z == x + y)
                    return true;
            }
        }
    }

    // If we reach here, no triplet found
    return false;
}


int main()
{
    int ar[] = { 10, 4, 6,12, 5 };
    int ar_size = sizeof(ar) / sizeof(ar[0]);
    isTriplet(ar, ar_size) ? cout << "Yes" : cout << "No";
    return 0;
}
Output

Yes

QUESTIONS) Program for factorial of a number

Input

7 Solution: PYTHON PROGRAM 

// C++ program for factorial of a number
#include <iostream>
using namespace std;

unsigned int factorial(unsigned int n)
{
    int res = 1, i;
    for (i = 2; i <= n; i++)
        res *= i;
    return res;
}

// Driver code
int main()
{
    int num = 7;
    cout << "Factorial of "
        << num << " is "
        << factorial(num) << endl;
    return 0;
}

C++ PROGRAM

def factorial(n):
    
    res = 1
    
    for i in range(2, n+1):
        res *= i
    return res


num = 7;
print("Factorial of", num, "is",
factorial(num))

Output

Factorial of 7 is 120

QUESTIONS) Find Second largest element in an array

Input

{4,7,19,17,11}

Solution:

PYTHON PROGRAM

#include <iostream>
#include<bits/stdc++.h>
using namespace std;

int main() {

    vector<int>v{4,7,19,17,11};
    set<int>s(v.begin(),v.end());
    v.clear();
    for(auto it:s)v.push_back(it);

    int n=v.size();
    
    cout<<"The Second Largest Element in Vector is: ";
    cout<<v[n-2]<<endl;
    return 0;
}

C++ PROGRAM

# your code goes here



v = [4, 7, 19, 17, 11]

s = set(v)

s = sorted(s)

print("The Second Largest Element in Vector is: ",s[-2])

Output 

The Second Largest Element in Vector is: 17 QUESTIONS) Check if the sum of digits of N is palindrome Input 

92 Solution: PYTHON PROGRAM 

#include <bits/stdc++.h>
using namespace std;

int main()
{
    int num = 92;
    int sum = 0;

    while (num != 0) {
        int temp = (num % 10);
        sum = sum + temp;
        num /= 10;
    }


    string str = to_string(sum);

    string string_rev = "" + str;
    reverse(string_rev.begin(), string_rev.end());

    cout << ((str == string_rev) ? "Yes" : "No");
}
C++ PROGRAM

#include <bits/stdc++.h>
using namespace std;

int main()
{
    int num = 92;
    int sum = 0;

    while (num != 0) {
        int temp = (num % 10);
        sum = sum + temp;
        num /= 10;
    }


    string str = to_string(sum);

    string string_rev = "" + str;
    reverse(string_rev.begin(), string_rev.end());

    cout << ((str == string_rev) ? "Yes" : "No");
}

Output 

Yes

Follow regularly our Dailyrecruitment.in site to get upcoming all up to date information.

JOB ALERT ON INSTAGRAM	FOLLOW NOW>>
JOB ALERT ON TELEGRAM	JOIN NOW>>